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X^2-33X+270=0
a = 1; b = -33; c = +270;
Δ = b2-4ac
Δ = -332-4·1·270
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-3}{2*1}=\frac{30}{2} =15 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+3}{2*1}=\frac{36}{2} =18 $
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